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 Putnam Solutions

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nick
Euclid
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Posts : 95
Join date : 2009-09-15
Age : 56
Location : Alexandria

PostSubject: Putnam Solutions   Tue Nov 09, 2010 1:32 pm

1985.pdf A-1

Solution

The required number is the potential of [Lin3°Ens]10,
= the coefficient of x10 in the e.g.f. of x3°exp(x)
= 310
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